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A source S is kept directly behind the slit `S_(1)` in a double slit apparatus. What will be the phase difference at P, if a liquid of refraction index `mu`is filled : (wavelength of light in aire is `lambda` due to the source, assume `lgtgtd,Dgtgtd`). (a) Between the screen and the slits. (b) Between the slits & the source S. In this case, find the minimum distance between the points on the screen where the intensity is half the maximum intensity on the screen.

Answer» Correct Answer - `[(a)Deltaphi=((1)/(l)+(mu)/(D))(pid^(2))/(lambda);(b) Deltaphi=((mu)/(l)+(1)/(D))(pid^(2))/(lambda);D_("min")=(beta)/(2)=(lambdaD)/(2d)]`


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