1.

A source S of acoustic wave of frequencyv_(0) = 1700Hz and a recelverR are located at the same point . At the instant t = 0 , the source starts from rest to move away from the receiver with a constant acceleration omega. The velocity of sound in air is v = 340 ms^(-1) .Ifomega = 10 m * s^(-2), the apparcent frequency that will be recorded by the stationary receiver at t = 10 s will be

Answer»

1700 HZ
1.35 Hz
850 Hz
1.27 Hz

SOLUTION :N/A


Discussion

No Comment Found