1.

A source whistling a sound of frequency 450 Hz moves towards a stationary listener with a speed of 33 m/s. If velocity of sound is 333 m/s, then find frequency of sound heard by this listener.

Answer»

409
429
517
500`

Solution :
We have, `(f _(L))/( v + v _(L)) = (f _(S))/( v + v _(S))`
`THEREFORE ( f _(L))/( 333 + 0) = (450)/(333-33)`
`therefore f _(L) = 450 XX (333)/(300)= 499.5Hz ~~ 500HZ`


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