A speaks the truth in 75% cases and B in 80% of the cases. In what per

1.	A speaks the truth in 75% cases and B in 80% of the cases. In what percentage of the cases are they to contradict each other in stating the same fact ?
Answer» For A, P(A) = 75/100 = 3/4 P(A') = 1 - (3/4) = 1/4 For B, P(B) = 80/100 = 4/5 P(B') = 1 - (4/5) = 1/5 P(A ∩ B') + P(A' ∩ B) = P(A) x P(B') + P(A') x P(B) = (3/4) x (1/5) + (1/4) x (4/5) = (3/20) + (4/20) = (7/20) x 100 = 35%

A speaks the truth in 75% cases and B in 80% of the cases. In what percentage of the cases are they to contradict each other in stating the same fact ?

Answer»

For A, P(A) = 75/100 = 3/4

P(A') = 1 - (3/4) = 1/4

For B, P(B) = 80/100 = 4/5

P(B') = 1 - (4/5) = 1/5

P(A ∩ B') + P(A' ∩ B) = P(A) x P(B') + P(A') x P(B)

= (3/4) x (1/5) + (1/4) x (4/5)

= (3/20) + (4/20)

= (7/20) x 100

= 35%

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A speaks the truth in 75% cases and B in 80% of the cases. In what percentage of the cases are they to contradict each other in stating the same fact ?

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