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A speaks truth in 605 cases and `B`speaks truth in 70% cases. The probability that they will say the samething while describing a single event is`2//19`b. `3//29`c. `17//19`d. `4//29`A. 0.56B. 0.54C. 0.38D. 0.94 |
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Answer» Correct Answer - B Consider the following events : `A_(1):a` speaks truth `A_(2):B` speaks truth then ,`P(A_(1))=60//100=3//5,P(A_(2))=70//100=7//10` for the required event either both of then should Speck the truth or both of them should tell a lie thus , the required probaility is `P((A_(1)nnA_(2))cup(barA_(1)nnbarA_(2)))` `=p(barA_(1)nnA_(2))+P(barA_(1)nnbarA_(2))` `=P(A_(1))P(A_(2))+P(barA_(1)nn barA_(2))` ` =P(A_(1))P(A_(2))+P(barA_(1))P(barA_(2))` `(3)/(5)xx(7)/(10)+(1-(3)/(5))(1-(7)/(10))` `=0.54` |
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