InterviewSolution
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InterviewSolution
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A speaks truth in 75% of the cases and B in 80% of the cases, what is the probabthat their statements about an incident do not match.57.. Let A.B denote the events of speaking truth by A.B respectively75 3100 480 4100 5TRUTH TELLLet E be the event that A and B contradict to each othernBu (An B) | = P(An B) + P(A-P(A)P(B)+PA)PB) A,B are indeper31 14 745 45 20o 113 and |
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Answer» Let A = Event that A speaks the truthB = Event that B speaks the truth Then P(A) = 75/100 = 3/4P(B) = 80/100 = 4/5 P(A-lie) = 1-3/4 = 1/4P(B-lie) = 1-4/5 = 1/5 NowA and B contradict each other =[A lies and B true] or [B true and B lies]= P(A).P(B-lie) + P(A-lie).P(B)[Please note that we are adding at the place of OR]= (3/5*1/5) + (1/4*4/5) = 7/20= (7/20 * 100) % = 35% Like my answer if you find it useful! |
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