1.

A specific gravity bottle weighs 20.5 gm when it is empty. When it is filled with a liquid at 20^(@)C it weighs 45.2 gm. The bottle with the liquid at 100^(@)C weighs 43.2 gm. Calculate the coefficient of apparent expansion of the liquid.

Answer»

Solution :wt. of the empty specific gravity BOTTLE `(W _(1)) = 20.5 gm`
wt. of the bottle + liquid at `20^(@)C (w _(2)) = 45.2 gm,` wt. of the bottle+ liquid at `100^(@)C (w _(3)) =43.2 gm`
`gamma _(a) = (w _(2) - w _(3))/((w _(3) - w _(1)) (t _(2) -t _(1))) = (45.2 - 43.2 )/((43.2 - 20.5 ) ( 100 - 20)) = (2)/( 22.7 xx 80) = (2)/( 1816) = 0.001 1 01 //^(@)C`
`THEREFORE` COEFFICIENT of apparent expansion `= 11.01 xx 10 ^(-4) // ^(@)C`


Discussion

No Comment Found