1.

A sphere can roll on a surface inclined at an angle 0 if the friction coefficient is more than 2/7 g tanθ. Suppose the friction coefficient is 1/7 g tanθ. If a sphere is released from rest on the incline,(a) it will stay at rest(b) it will make pure translational motion(c) it will translate and rotate about the centre(d) the angular momentum of the sphere about its centre will remain constant.

Answer»

(c) it will translate and rotate about the centre

Explanation: 

Since there is some friction which will produce a torque on the sphere and there is no othe torque to balance it. Hnce the sphere will not stay at rest. Option (a) is not correct. Due to the torque produced by the friction it will have some rotational motion also. Hence option (b) is not correct. 

From the question, the friction coefficient is =(1/7)g.sinθ which is lessthan (2/7)g.sinθ {required for rolling only} so it will translate and rotate about the center. Option (c) is correct. 

As the sphere go down the inclined plane its angular velocity will get increasing. So the angular momentum of the sphere about its center will continue increasing. Option (d) is not correct.



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