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A sphere of diameter 15.6 cm is melted and cast into a right circular cone of height 31.2 cm. Find the diameter of the base of the cone. |
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Answer» It is given that Diameter of the sphere = 15.6 cm Radius of the sphere = 15.6/2 = 7.8 cm Height of the cone = 31.2 cm We know that 4/3 πR3 = 1/3 πr2h So we get 4/3 × (22/7) × 7.83 = 1/3 × (22/7) × r2 × 31.2 On further calculation r2 = (4/3 × (22/7) × 7.83)/ (1/3 × (22/7) × 31.2) So we get r2 = (4 × 474.552)/ 31.2 = 60.84 By taking square root on the RHS r = 7.8cm Diameter = 2 (7.8) = 15.6cm Therefore, the diameter of the base of the cone is 15.6cm. |
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