1.

A sphere of diameter 15.6 cm is melted and cast into a right circular cone of height 31.2 cm. Find the diameter of the base of the cone.

Answer»

It is given that

Diameter of the sphere = 15.6 cm

Radius of the sphere = 15.6/2 = 7.8 cm

Height of the cone = 31.2 cm

We know that

4/3 πR3 = 1/3 πr2h

So we get

4/3 × (22/7) × 7.83 = 1/3 × (22/7) × r2 × 31.2

On further calculation

r2 = (4/3 × (22/7) × 7.83)/ (1/3 × (22/7) × 31.2)

So we get

r2 = (4 × 474.552)/ 31.2 = 60.84

By taking square root on the RHS

r = 7.8cm

Diameter = 2 (7.8) = 15.6cm

Therefore, the diameter of the base of the cone is 15.6cm.



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