A sphere of mass 1 kg rests at one corner of a box. The box is then moved with a velocity →v=8t ^i−2t2^j. Where t is time in second. The force by sphere on the box at t=1 s is (g=10 ms−2) [Figure shows vertical plane of the box]

A sphere of mass 1 kg rests at one corner of a box. The box is then m

1.	A sphere of mass 1 kg rests at one corner of a box. The box is then moved with a velocity →v=8t ^i−2t2^j. Where t is time in second. The force by sphere on the box at t=1 s is (g=10 ms−2) [Figure shows vertical plane of the box]
Answer» A sphere of mass $1 kg$ rests at one corner of a box. The box is then moved with a velocity $\to v = 8 t^i - 2 t^{2}^j$ . Where $t$ is time in second. The force by sphere on the box at $t = 1 s$ is ( $g = 10 {ms}^{- 2}$ ) [Figure shows vertical plane of the box]

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A sphere of mass 1 kg rests at one corner of a box. The box is then moved with a velocity →v=8t ^i−2t2^j. Where t is time in second. The force by sphere on the box at t=1 s is (g=10 ms−2) [Figure shows vertical plane of the box]

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