1.

A sphere of mass 10 kg and radius 0.5 m rotates about a tangent. The moment of inertia of the sphere is

Answer»

5 kg `m^(2)`
`2.7` kg `m^(2)`
3.5 kg `m^(2)`
4.5 kg `m^(2)`

Solution :MOMENT of INERTIA about tangent = `I+ MR^(2) = (2)/(5) MR^(2) + MR^(2) = (7)/(5) MR^(2) = (7)/(5) XX (10) xx (0.5)^(2) = 3.5 kg m^(2)`


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