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A sphere of mass 50 xx 10^(-3) kg moving with a velocity of 2 ms^(-1) hits another sphere which is at rest. Assuming the collision to be head - on collision and it they stick together after collision and move in the same direction with a velocity of 0.5 ms^(-1), find the moss of the second sphere

Answer»

SOLUTION :`50 xx 10^(-3) kg, u_(1) = 2 ms^(-1), u_(2) = 0.`
`v = 0.5 ms^(-1), v = v_(1) = v_(2) = 0.5 ms^(-1)`.
`m_(1)u_(1) + m_(2)u_(2) = (m_(1) + m_(2)) v`
`(50xx10^(-3))(2)+m^(2)(0)=[(50xx10^(-3))+m^(2)]0.5`
`m_(2)=(50xx10^(-3)xx2-50xx10^(-3)xx0.5)/(0.5)`
`=((100-25)/(0.5))xx10^(-3)=150xx10^(-3)kg`


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