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A sphere of radius R and density `rho_1` is dropped in a liquid of density `sigma`. Its terminal velocity is `v_1`. If another sphere of radius `R` and density `rho_2` is dropped in the same liquid, its terminal velocity will be:A. `v[p_(2)+sigma)//p_(1)+sigma)]`B. `v[p_(1)+sigma)//p_(2)+sigma)]`C. `v[p_(2)-sigma)//p_(1)-sigma)]`D. `v[p_(1)-sigma)//p_(2)-sigma)]` |
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Answer» Correct Answer - C The terminal velocity of the sphere `v =(2)/(9)R^(2) ((rho^(2) - sigma)g)/(eta)" ".....(i)` Here ,R = radius of sphere `rho_(1)` = density of sphere and `sigma` = density of liquid . Now if density of metal sphere is changed to `rho_(2)` then terminal velocity `v_(2) (2)/(9)(R^(2) (rho_(2) - sigma)g)/((rho_(1) - sigma)) or (v_(2)(rho_(2) - sigma))/((rho_(1) - sigma))` Hence , the terminal velocity is `(v(rho_(2)-sigma))/(rho_(1)-sigma)` |
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