A sphere rolls down in an inclined plane without slipping. The percentage of translational energy in its total energy is

A sphere rolls down in an inclined plane without slipping. The percent

1.	A sphere rolls down in an inclined plane without slipping. The percentage of translational energy in its total energy is
Answer» <html><body><p>`29.6%`<br/>`33.4%`<br/>`71.4%`<br/>`50%`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/rotational-625601" style="font-weight:bold;" target="_blank" title="Click to know more about ROTATIONAL">ROTATIONAL</a> `K.E .E_("rot")=(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)/(2) omega^(2)=(1)/(2)((2)/(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>)MR^(2)) omega^(2)=(1)/(5)MR^(2) omega^(2)` <br/> Translational K.E `(E_("<a href="https://interviewquestions.tuteehub.com/tag/trans-1425477" style="font-weight:bold;" target="_blank" title="Click to know more about TRANS">TRANS</a>"))=(1)/(2)Mv^(2)=(1)/(2)MR^(2)omega^(2)` <br/> `E_("rot")=E_("rot")+E_("trans") =(1)/(5) MR^(2)+(1)/(2) MR^(2) omega^(2)=(7)/(10) MR^(2) omega^(2)` <br/> `%"of" E_("trans")=(E_("trans"))/(E_("Tot"))xx100%=(5)/(7)%=71.4%`</body></html>