A spherical ball A of mass 4 kg, moving along a straight line strikes another spherical ball B of mass 1 kg at rest. After the collision, A and B move with velocities v_1 ms^(-1) and v_2 m s^(-1) respectively making angles of 30^@and 60^(@) with respect to the original direction of motion of A. The ratio (v_1)/(v_2) will be

A spherical ball A of mass 4 kg, moving along a straight line strikes

1.	A spherical ball A of mass 4 kg, moving along a straight line strikes another spherical ball B of mass 1 kg at rest. After the collision, A and B move with velocities v_1 ms^(-1) and v_2 m s^(-1) respectively making angles of 30^@and 60^(@) with respect to the original direction of motion of A. The ratio (v_1)/(v_2) will be
Answer» `(sqrt3)/(4)` `4/(sqrt3)` `1/(sqrt3)` `sqrt(3)` Solution : Applying the law of CONSERVATION of linear momentum ALONG a direction perpendicular to the direction of MOTION (i.e., along y -AXIS) , we get `0 + 0 = 4v_1 sin 30^@ - v_2 sin 60^@` `(v_1)/(v_2) = (sin 60^@)/(4 sin 30^@) = (sqrt3)/(4)`.