InterviewSolution
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InterviewSolution
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A spherical conductor A of radius r is placed concentrically inside a conducting shell B of radius R (R < r). A charge Q is given to A, and then A is joined to B by a metal wire. The charge flowing from A to B will be(a) Q(R/R + 1)(b) Q(R/ + r(c) Q(d) zero |
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Answer» Correct Answer is: (c) Q Method 1: When the two are joined by a metal wire, they become a single conductor. As charge can reside only on the outer surface of a conductor, the entire charge Q must flow to the outer sphere. Method 2: When charge of amount q has flown from A to B, the charge on A is (Q - q). VA = k Q-q/r +k q/R VB = k Q-q/R ∴ VA - VB = k(Q - q) (1/r - 1/R) > 0 ∴ VA > VB for all values of q. Charge will flow from A to B till q = Q. |
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