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A spherical planet far out in space has a mass `M_(0)` and diameter `D_(0)`. A particle of mass m falling freely near the surface of this planet will experience an accelertion due to gravity which is equal to |
Answer» `g_(p)=(GM_(p))/(R_(p)^(2))` Here, `M_(p)=M_(0)` `R_(p)=(1)/(2)D_(0)` `therefore g_(p)=(GM_(0))/(((1)/(2)D_(0))^(2))` `therefore g_(p)=(4GM_(0))/(D_(0)^(2))` |
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