InterviewSolution
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InterviewSolution
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A spherical surface of radius of curvature R separates air (refractive index 1.0) from glass (refractive index 1.5). The centre of curvature is in the glass. A point object P placed in air is found to have a real image Q in the glass. The line PQ cuts the surface at a point O, and `PO=OQ`. The distance `PO`A. 5 RB. 3 RC. 2 RD. `1.5 R` |
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Answer» Correct Answer - A Here, `mu_1 = 1, mu_2 = 1.5`, Let `PO = OQ =x` As light is travelling from Rerer to Denser medium, `:. (mu_1)/(-u) + (mu_2)/(v) = (mu_2 - mu_1)/( R)` `:. (1)/(-(-x)) + (1.5)/(x) = (1.5 - 1)/( R)` `(1)/(x) + (1.5)/(x) = (0.5)/( R)` or `(2.5)/(x) = (0.5)/( R)` or `x = 5 R`. |
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