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A spring 40 mm long is stretched by the application of a force . If 10 N force required to stretchthe springthrough40 mm is …….. |
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Answer» 23 J stretching in the springx = 1 mm = `0.001 ` m spring constant `k = F/x =10/(1xx10^(-3)) = 10^(4)` Now springis stretching through a distance `x_(1) = 40 mm = 0.04 m ` The force requiredto stretch is through `x_(1)` is `F_(1) =kx_(1)` ` :. ` The work done by the force `W = 1/2 kx_(1)^(2) =1/2 kx_(1) xxx_(1)` ` = 400/2 xx0.004` = 8 J |
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