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A spring balance has a scale that reads `0` to `20kg`. The length of the scale is `10cm`. A body suspended from this balance, when displaced and released, oscillates with period of `(pi)/(10)s`. The mass of the body isA. 350.67 NB. 540.11 NC. 311.24 ND. 300.5 N |
Answer» Correct Answer - C Time period of the spring mass system, `T = 2pi sqrt((m)/(k))" "...(i)` From spring, mg = kx `rArr" "k=(mg)/(x)=(60 xx 9.8)/(30 xx 10^(-2))=1960 Nm^(-1)" "...(ii)` From Eqs. (i) and (ii), we get `0.8 = 2pi sqrt((m)/(1960))` `rArr" "(0.8 xx 0.8 xx 1960)/(4 pi^(2))=m` `m = 31.81 kg" "rArr" "w = mg` `w = 31.81 xx 9.8 = 311.24 N` |
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