1.

A spring balance has a scale that reads from 0 to 50 kg. The length of the scale is 20 cm. A body suspended from this spring, when displaced and released, oscillates with period of 0.60 s. What is the weight of the body?

Answer»

Solution :Here, m =50kg, Max. extension,y=20-0=20 cm=0.2 m,T=0.6s,
Max. Force. F = mg =`50xx9.8 N therefore K = F/y = (50xx9.8)/(0.2) =2450 Nm^(-1)`
Therefore As `T= 2pi SQRT(m/k) , m = (T^2 k)/(4pi^2) = ((0.6)^2 xx 2450)/(4XX(3.14)^2) = 22.36`kg
`therefore ` Weight of BODY = mg `= 22.36 xx 9.8 = 219.1 N`


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