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A spring balance has a scale that reads from 0 to 50 kg. The length of the scale is 20 cmA body suspended from this balance, when displaced and released, oscillates with a period of 0.6s. What is the weight of the body? |
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Answer» Length of the scale = 20 cm = 0.20 m Total scale reading = 50 kg Scale reading per unit length of the scale = 50/0.20 = 250 kg m-1 Now, the time-period of oscillation, T = 0.6 s Hence, T = 2π√{l/g} ⇒ l = {T2g}/{4π2} = {(0.6)2 x 9.8}/{4 x 9.87} = 0.089 m Reading on the scale corresponding to the length l is = 250 x 0.089 kg = 22.34 kg = 22.34 x 9.8 N = 219 N |
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