1.

A spring balance has a scale that reads from 0 to 50 kg. The length of the scale is 20 cmA body suspended from this balance, when displaced and released, oscillates with a period of 0.6s. What is the weight of the body?

Answer»

Length of the scale = 20 cm = 0.20 m

Total scale reading = 50 kg

Scale reading per unit length of the scale = 50/0.20 = 250 kg m-1

Now, the time-period of oscillation, T = 0.6 s

Hence, T = 2π√{l/g} ⇒ l = {T2g}/{4π2}

= {(0.6)2 x 9.8}/{4 x 9.87} = 0.089 m

Reading on the scale corresponding to the length l is

= 250 x 0.089 kg

= 22.34 kg

= 22.34 x 9.8 N = 219 N



Discussion

No Comment Found

Related InterviewSolutions