1.

A spring balance is attached to the ceiling of a lift. When the lift is at rest spring balance reads 49 N of a body hang on it. If the lift moves:1. Downward 2. upward, with an acceleration of 5 ms2 3. with a constant velocity.What will be the reading of the balance in each case?

Answer»

1. R = m(g – a) = 49 N 

so = m = \(\frac{49}{9.8}\) = 5 kg 

R = 5 (9.8 – 5) 

R = 24 N 

2. R = m(g + a) 

R = 5 (9.8 + 5) 

R = 74 N 

3. as a = 0 so R = mg = 49 N



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