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A spring is stretched by 3cm when a load of `5.4 × 10^(6)` dyne is suspended from it. Work done will be-A. `8.1xx10^(6)` ergB. `6.1xx10^(6)` ergC. `5.1xx 10^(6)`ergD. `4.1xx 10^(6)`erg |
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Answer» Correct Answer - A Work done `=(1)/(2)xx` stretching force `xx` elongation `W=(1)/(2)xx5.4xx10^(6)xx3=8.1xx10^(6)erg` |
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