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A spring of force constant 1200 Mm^(-1) Is mounted on a horizontal table as shown in Fig. A mass of 3.0 kg is attached to the free end of the spring, pulled side ways to a distance 2.0 cm and released. Determine the frequency of oscillation of the mass |
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Answer» Solution :Here , `K= 1200Nm^(-1), m= 3.0 kg, A= 2.0 cm = 0.02m` FREQUENCY , `f= (1)/(T)= (1)/(2A)SQRT((k)/(m))= (1)/(2 XX 3.14)sqrt((1200)/(3))= 3.2 s^(-2)` |
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