A spring of force constant 1200 Mm^(-1) Is mounted on a horizontal table as shown in Fig. A mass of 3.0 kg is attached to the free end of the spring, pulled side ways to a distance 2.0 cm and released. Determine the maximum acceleration of the mass.

A spring of force constant 1200 Mm^(-1) Is mounted on a horizontal tab

1.	A spring of force constant 1200 Mm^(-1) Is mounted on a horizontal table as shown in Fig. A mass of 3.0 kg is attached to the free end of the spring, pulled side ways to a distance 2.0 cm and released. Determine the maximum acceleration of the mass.
Answer» Solution :Here , `k= 1200NM^(-1), m= 3.0 kg, A= 2.0 CM = 0.02m` ACCELERATION `a= omega^(2)y= (k)/(m)y` Acceleration will be maximum when y is maximum i.e. y=A `:. "Max. acceleration" , a_("max")= (kA)/(m)= (1200xx 0.02)/(3)= 8ms^(-2)`