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A spring of force constant 1200 Nm^(-1) is mounted on a horizontal table as shown in Fig. A mass of 3.0 kg is attached to the free end of the spring, pulled side ways to a distance 2.0 cm and released. Determinethe frequency of oscillation of the mass. |
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Answer» Solution :Here, `k=1200 NM^(-1) , m= 3.0 kg , A = 2.0 cm = 0.02 m` (a) Frequency , `f= 1/T = 1/(2A) SQRT(k/m) = 1/(2xx3.14) sqrt((1200)/(3)) = 3.2 s^(-s)` |
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