A spring of force constant 1200 Nm^(-1) is mounted on a horizontal table and a mass of 3.0 kg of attached to the free and of the spring. The mass is made to rotate with an angular velocity of 10 rad/s. What is the elongation produced in the spring if its unstretched length is 60 cm ?

A spring of force constant 1200 Nm^(-1) is mounted on a horizontal tab

1.	A spring of force constant 1200 Nm^(-1) is mounted on a horizontal table and a mass of 3.0 kg of attached to the free and of the spring. The mass is made to rotate with an angular velocity of 10 rad/s. What is the elongation produced in the spring if its unstretched length is 60 cm ?
Answer» Solution :`m(l +x)omega^(2) = KX, x = mkomega^(2)lk-momega^(2) = 3 xx 0.60xx 10^(2)//1200 - 3 xx 10^(2) = 0.2 m`