A spring of force constant 800 N m^(-1)has an extension of 5 cm. The work done in extending it from 5 cm to 15 cm is

A spring of force constant 800 N m^(-1)has an extension of 5 cm. The w

1.	A spring of force constant 800 N m^(-1)has an extension of 5 cm. The work done in extending it from 5 cm to 15 cm is
Answer» 16J 8J 32J 24 J Solution :`W = 1/2 K(x_2^2 - x_1^2)` `=1/2 xx 800[(15 xx 10^(-2))^(2) - (5 xx 10^(-2))^(2)]` `= 400 xx 200 xx 10^(-4) = 8 J` .