1.

A spring of force constant 'k' is cut into two pieces such that one piece is double the length of the other. Then the long piece will have a force constant of ……………

Answer»

`(2)/(3) k`
`(3)/(2)k`
3k
6 k

Solution :Ratio in which spring is cut = 1:2
Length of LARGER piece `=(2L)/3`
FORCE constant `prop =1/("length of the spring")`
`K/K. = (((2L)/3))/L = 2/3 , K. =3/2 K`


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