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A spring of force constant 'k' is stretched by a small length 'x'. Find the work done in stretching it further by a small length 'y'. |
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Answer» Solution :Let `W_(1)` is the work DONE in STRETCHING a spring of FORCE CONSTANT .K. through a length ..x... Then `W_(1)= (1)/(2) Kx^(2)` Let `..W_(2)..` is the workdone is stretching the spring through a length `(x+y)`. Then `W_(2)= (1)/(2)K(x+ y)^(2)` `THEREFORE` Additional work done, to increase the elongation by ..y.. is `W= W_(2)-W_(1)` `W=(1)/(2) K (x+y)^(2) - (1)/(2) Kx^(2)`
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