A spring of spring constant 5 xx 10^3. N m^(-1) is stretched initially by 5 cm from the unstretched position. The work required to stretch it further by another 5 cm is

A spring of spring constant 5 xx 10^3. N m^(-1) is stretched initially

1.	A spring of spring constant 5 xx 10^3. N m^(-1) is stretched initially by 5 cm from the unstretched position. The work required to stretch it further by another 5 cm is
Answer» 6.25 Nm 1250 Nm 18.75 Nm 25.00 Nm Solution :`U_1 = 1/2 kx_1^2 = 1/2 XX (5 xx 10^3) xx (5 xx 10^(-2))^(2) = 6.25 N m` `U_2 = 1/2 kx_2^2 = 1/2 xx 5 xx 10^(3) xx (5 + 5)^2 xx 10^(-4)= 25 Nm`. `:. ` WORK done = `U_2 - U_1 = 25.0 Nm - 6.25 N m = 18.75 Nm`.