A spring when compressed by 0.2 m develops a restoring force of 50 N. If a body of mass 10 kg is placed on it, calculate (i) the force constnat (I) of the spring (ii) the depression of the spring (iii) time period of oscillation when the weight is slightly displaced from equilibrium position.

A spring when compressed by 0.2 m develops a restoring force of 50 N.

1.	A spring when compressed by 0.2 m develops a restoring force of 50 N. If a body of mass 10 kg is placed on it, calculate (i) the force constnat (I) of the spring (ii) the depression of the spring (iii) time period of oscillation when the weight is slightly displaced from equilibrium position.
Answer» <html><body><p></p>Solution :(i) The <a href="https://interviewquestions.tuteehub.com/tag/force-22342" style="font-weight:bold;" target="_blank" title="Click to know more about FORCE">FORCE</a> constant `<a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>=F/x=50/0.2=250Nm^(-1)` <br/> (ii) depression of the <a href="https://interviewquestions.tuteehub.com/tag/spring-11487" style="font-weight:bold;" target="_blank" title="Click to know more about SPRING">SPRING</a> `(mg)/k=(10xx9.8)/250=0.392m` <br/> (<a href="https://interviewquestions.tuteehub.com/tag/iii-497983" style="font-weight:bold;" target="_blank" title="Click to know more about III">III</a>) Time period <br/> `T=2pisqrt(m/k)=2pisqrt(10/250)=(2xx3.14)/5=1.2568s`</body></html>