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A spring when stretched upto 2 cm has potential energy u. If it is stretched upto 10 cm, potential energy would beA. u/25B. u/5C. 5 uD. 25 u

Answer» Correct Answer - D
`u_(1)=(1)/(2)kx_(1)^(2)andu_(2)=(1)/(2)kx_(2)^(2)`
`(u_(2))/(u_(1))=(x_(2)^(2))/(x_(1)^(2))thereforeu_(2)(uxx100)/(4)=25u`


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