A square coil whose each side is 10 cm has 20 turns and 12 A current is flowing. The coil is hanging vertically and a perpendicular drawn from the plane of this makes an angle 30° with the uniform magnetic field of 0. 80 T. How much is the magnitude of torque acting on the coil?

A square coil whose each side is 10 cm has 20 turns and 12 A current i

1.	A square coil whose each side is 10 cm has 20 turns and 12 A current is flowing. The coil is hanging vertically and a perpendicular drawn from the plane of this makes an angle 30° with the uniform magnetic field of 0. 80 T. How much is the magnitude of torque acting on the coil?
Answer» Side of square coil = 10 cm ∴ Area of coil A = (10)² = 100cm² = 10^-2 m² Current flowing I = 12 A Number of turns in coil N = 20 Magnetic field B = 0.80 T Angle θ = 30° Torque acting on coil τ = NIABsinθ τ = 20 × 10^-2 × 12 × 0.80 × sin 30° τ = 20 × 12 × 0.80 × \(\frac{1}{2}\) × 10^-2 τ = 0.96 N-m