A square lead slab of side 50 cm and thickness 10.0 cm is subjected to a shearing force (on its narrow face) of magnitude 9.0xx10^(4)N. The lower edge is riveted to the floor. How much is the upper edge displaced, if the shear modulus of lead is 5.6xx10^(9) Pa?

A square lead slab of side 50 cm and thickness 10.0 cm is subjected to

1.	A square lead slab of side 50 cm and thickness 10.0 cm is subjected to a shearing force (on its narrow face) of magnitude 9.0xx10^(4)N. The lower edge is riveted to the floor. How much is the upper edge displaced, if the shear modulus of lead is 5.6xx10^(9) Pa?
Answer» Solution : Here `L=50cm=50xx10^(-2)m,G=5.6xx10^(9)Pa,F=9.0xx10^(4)N`. Area of the FACE on which force is applied, `A=50xx10=500sq.cm=0.05m^(2)` If `DELTAL` is the displacement of the UPPER edge of the SLAB due to tangential force F applied, then `G=(F//A)/(DeltaL//L)` (or)`DeltaL=(FL)/(GA)` `=(9xx10^(4)xx50xx10^(-2))/(5.6xx10^(9)xx0.05)=1.6xx10^(-4)m`