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A square metal plate of 10 cm side moves parallel to another plate with a velocity of 10 cm s^(-1), both plates immersed in water. If the viscous force is 200 dyne and viscosity of water is 0.01 poise. What is their distance apart ? |
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Answer» SOLUTION :Here, `A = 10 xx 10 = 100cm^2 , dv = 10 cm s^(-1), eta = 0.01 "poise", F = 200` DYNE As `"" F = eta A (dv)/(DX)` `"" dx = (eta A dv)/(F) = (0.01 xx 100 xx 10)/(200) , dx = 0.05 cm` |
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