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A square pyramid is to be made with the triangles shown here as a lateral face. What I would be its height? What if the base edge is 40 centimetres instead of 30 centimetres? |
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Answer» Slant height = \(\sqrt{25^2-15^2}\) = \(\sqrt{625-225}\) = \(\sqrt{400}\) = 20 cm Height = \(\sqrt{20^2-15^2}\) = 13.2 cm Let base edge be 40 cm Slant height = \(\sqrt{20^2-20^2}\) = \(\sqrt{625-400}\) = \(\sqrt{225}\) = 15 cm Height = \(\sqrt{15^2-15^2}\) = 0 It is impossible to make a square pyramid of base edge 40cm. |
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