A standing wave on a string is given by `y = ( 4 cm) cos [ x pi] sin [ 50 pi t]`, where `x` is in metres and t is in seconds. The velocity of the string section at `x = 1//3 m at t = 1//5 s`, isA. zeroB. ` pi m//s`C. `840 pi m//s`D. noneof these

A standing wave on a string is given by `y = ( 4 cm) cos [ x pi] sin [

1.	A standing wave on a string is given by `y = ( 4 cm) cos [ x pi] sin [ 50 pi t]`, where `x` is in metres and t is in seconds. The velocity of the string section at `x = 1//3 m at t = 1//5 s`, isA. zeroB. ` pi m//s`C. `840 pi m//s`D. noneof these
Answer» Correct Answer - B velocity of the string section can be given as `v = ( delta y)/( delta t) = 4 cos pi x xx (50 pi) cos ( 50 pi t)` ` v = 4 cos [ pi xx (1)/(3)] xx 50 pi cos [ 50 pi xx (1)/( 5)]` `= 200 pi xx (1)/(2) xx 1 = 100 pi cm//s = pi m//s`

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A standing wave on a string is given by `y = ( 4 cm) cos [ x pi] sin [ 50 pi t]`, where `x` is in metres and t is in seconds. The velocity of the string section at `x = 1//3 m at t = 1//5 s`, isA. zeroB. ` pi m//s`C. `840 pi m//s`D. noneof these

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