1.

A stationary body of mass 3 kg explodes into three equal pieces. Two of the pieces fly off in two mutually perpendicular directions, one with a velocityof 3hati" m s"^(-1). And the other with a velocity of 4hatj" m s"^(-1). If the explosion occurs in 10^(-4)" s", the average force acting on the third piece in newton is

Answer»

`(3HATI + 4haj)XX 10^-4`
`(3hati - 4haj)xx 10^-4`
`(3hai + 4hatj)xx 10^-4`
`(3hati + 4hatj ) xx 10^4)`

ANSWER :`-(3hati + 4 HATJ) xx 10^4`


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