1.

A stationary object is divided into two fragment of mass 2M and 3M. Total energy of both fragment is E. Find energy of fragment with mass 2M.

Answer»

`(2E)/(5)`
`(E )/(2)`
`(E )/(5)`
`(3E)/(5)`

Solution :By lawof conservationof energy
`(M_(1)+M_(2) ) V=2Mv_(1)- 3M v_(2)`
Where`M_(1) =2M,M_(2) = 3M V=0`
`2Mv_(1) =3M_(2)`
`v_(2) =(2)/(3) v_(1)`
`v_(2)^(2)= (4)/(9) v_(1)^(2)`
Totalenergy
`E= (1)/(2) .(2M)v_(1)^(2) + (1)/(2) (3M)v_(2)^(2)`
`=mv_(1)^(2) + (3)/(2)Mv_(2)^(2)`
`=mv_(1)^(2) + (2)/(3) Mv_(1)^(2)`
`E= (5)/(3) Mv_(1)^(2)`
Kineticenergy of 2Mpart
`E_(1) = (1)/(2) (2M) v_(1)^ (2)`
Takingratio of (2)and (3) `(E_(1))/(E ) = ((1)/(2) (2M)v_(1)^(2))/((5)/(3)Mv_(1)^(2))`
`E_(1) = (3)/(5)E`


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