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A stationary object is divided into two fragment of mass 2M and 3M. Total energy of both fragment is E. Find energy of fragment with mass 2M. |
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Answer» `(2E)/(5)` `(M_(1)+M_(2) ) V=2Mv_(1)- 3M v_(2)` Where`M_(1) =2M,M_(2) = 3M V=0` `2Mv_(1) =3M_(2)` `v_(2) =(2)/(3) v_(1)` `v_(2)^(2)= (4)/(9) v_(1)^(2)` Totalenergy `E= (1)/(2) .(2M)v_(1)^(2) + (1)/(2) (3M)v_(2)^(2)` `=mv_(1)^(2) + (3)/(2)Mv_(2)^(2)` `=mv_(1)^(2) + (2)/(3) Mv_(1)^(2)` `E= (5)/(3) Mv_(1)^(2)` Kineticenergy of 2Mpart `E_(1) = (1)/(2) (2M) v_(1)^ (2)` Takingratio of (2)and (3) `(E_(1))/(E ) = ((1)/(2) (2M)v_(1)^(2))/((5)/(3)Mv_(1)^(2))` `E_(1) = (3)/(5)E` |
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