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A stationary observer receives a sound from a source of frequency `2000Hz` moving with constant velocity. The apparent frequency varies with as shown in the figure The value of `f_(m)` is `(2300-10x)Hz`. Find the value of `x`. (Take speed of sound `=30m//s` and neglect the time taken by sound to reach the stationary observer). |
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Answer» `t_(m)=(v)/((v-v_(s)costheta)_("min"))xxf` `1800=(v)/((v+v_(s)costheta)_("min"))xxf` On solving `f_(m)=2250 Hz` `=2300-50` |
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