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A stationary observer receives a sound from a source of frequency 2000 Hz moving with constant velocity. The apparent frequency varies with time as shown in the figure. The value of fmax is (2300 - 10x) Hz. Then the value of x is(Take speed of sound = 300 m/s and neglect the time taken by sound to reach the stationary observer) |
Answer» A stationary observer receives a sound from a source of frequency 2000 Hz moving with constant velocity. The apparent frequency varies with time as shown in the figure.![]() The value of fmax is (2300 - 10x) Hz. Then the value of x is |
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