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A steel ball of mass 0.1 kg falls freely from a height of 10m and bounces to a height of 5.4m from the ground. If the dissipated energy in this process is absorbed by the ball, the rise in its temperature is (specific heat of steel = 460 JKg^(-1)K^(-1)) (g=10ms^(-2)) |
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Answer» `0.01^@C` |
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