Saved Bookmarks
| 1. |
A steel ball of mass 0.1 kg falls freely from a height of 10m an bounces to a height of 5.4m from the ground. If the dissipated energy in this process is absorbed by the ball, the rise in its temperature is (specific heat of steel=460JKg^(-1)K^(-1)) (g=10ms^(-2)). |
|
Answer» `0.01^(@)C` |
|