A steel ball of radius 2 xx 10^(-3) m is released in an oil of viscosity 0.232 Ns m^(-2) and density 840 kg m^(-3). Calculate the terminal velocity of ball. Take density of steel as 7800 kg m^(-3)

A steel ball of radius 2 xx 10^(-3) m is released in an oil of viscosi

1.	A steel ball of radius 2 xx 10^(-3) m is released in an oil of viscosity 0.232 Ns m^(-2) and density 840 kg m^(-3). Calculate the terminal velocity of ball. Take density of steel as 7800 kg m^(-3)
Answer» SOLUTION :` v= 2 xx ( 2XX 10 ^(-3))^(2)xx ( 7800 -840 ) xx 9.8 // 9 xx 0.232 = 0.26 ms ^(-1)`