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A steel cylinder of mass 2 kg contains 4 L of liquid water at 25°C at 200 kPa. Find the total mass and volume of the system. List two extensive and three intensive properties of the water |
Answer» Density of steel in ρ = 7820 kg/m3 Volume of steel: V = m/ρ = 2 kg/7820 kg/m3 = 0.000 256 m3 Density of water in ρ = 997 kg/m3 Mass of water: m = ρV = 997 kg/m3 ×0.004m3 = 3.988 kg Total mass: m = msteel + mwater = 2 + 3.988 = 5.988 kg Total volume: V = Vsteel + Vwater = 0.000 256 + 0.004 = 0.004 256 m3 = 4.26 L |
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