1.

A steel plate of face area2 cm^(2) and the thickness 1.0cm is fixed at the lower face. Atangential force of 10N is appliedon the upper surface. Find thelateral displacement of the upper surface withrespect to the lowersurface. Rigidity modulus of steel =8.4xx10^(10)Nm^(-2)

Answer»

Solution :`A = 2cm^2 = 2 xx 10^(-4) m^2 , L = 1.0cm = 1 xx 10^(-2)m, F = 10N, G = 8.4 xx 10^10 Nm^(-2) , l= ? , G = (FL)/(A DELTA x)`
The lateral displacementof the upper face with respect to the lower face is `Delta x = (FL)/(AG)`
` = (10 xx 1 xx 10^(-2))/(2 xx 10^(-4) xx 8.4 xx 10^10)`
` (1)/(16.8) xx 10^(-7) m = 5.952 xx 10^(-9) m`


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