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A steel ring of radius r and cross-sectional area A is fitted onto a wooden disc of radius R (R gt r). If the Young's modulus of steel is Y, then the force with which the steel ring is expanded is .......... |
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Answer» `AY (R )/(r )` Circumference of steel RING `L = 2pi r ` Increase in circumference of steel ring `l= 2pi R - 2pi r` `= 2pi (R-r)` STRAIN `= l/L = (2pi (R-r))/( 2pi r ) = (R-r)/(r)` Now, Young.s modulus `Y= ("stress")/("strain") = ((F)/(A))/( (R-r)/(r))` `therefore F = AY[ (R-r)/(r)]` |
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