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A steel rod of cross-sectional area1m^(2) is acted upon by forces shown in the fig. Determinethe totalelongation of the bar. Take Y=2.0xx10^(11)N//m^(2).

Answer» <html><body><p></p>Solution :The <a href="https://interviewquestions.tuteehub.com/tag/actionof-2398239" style="font-weight:bold;" target="_blank" title="Click to know more about ACTIONOF">ACTIONOF</a> forces on eachpartof rod is shown in fig. <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_NEO_CAO_PHY_XI_V01_PMH_C10_SLV_055_S01.png" width="80%"/> <br/> We know that the extension <a href="https://interviewquestions.tuteehub.com/tag/due-433472" style="font-weight:bold;" target="_blank" title="Click to know more about DUE">DUE</a> to external force F is given by `Delta_(AB)=(Fl)/(<a href="https://interviewquestions.tuteehub.com/tag/ay-386628" style="font-weight:bold;" target="_blank" title="Click to know more about AY">AY</a>)`<br/>`Deltal_(AB)=((<a href="https://interviewquestions.tuteehub.com/tag/60xx10-1908097" style="font-weight:bold;" target="_blank" title="Click to know more about 60XX10">60XX10</a>^(3))<a href="https://interviewquestions.tuteehub.com/tag/xx1-1463705" style="font-weight:bold;" target="_blank" title="Click to know more about XX1">XX1</a>.5)/(1xx2xx10^(11)) =4.5xx10^(-7)m` <br/> `Deltal_(BC)=((70xx10^(3))xx1)/( 1xx2xx10^(11)) =3.5xx10^(-7)m` <br/> and `Deltal_(CD)=((50xx10^(3))xx2)/(1xx2xx10^(11))=5.0xx10^(-7)m` <br/> The total extension `Delta=Delta_(AB)+Delta_(BC)+Delta_(CD)`<br/>`=4.5xx10^(-7)+3.5 xx 10^(-7)+5.0xx10^(-7)=13xx10^(-7)m`</body></html>


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